Equilateral and Equiangular Polygons

A polygon is a 2 dimensional geometric figure bound with straight sides. A polygon is called Equilateral if all of its sides are congruent. Common examples of equilateral polygons are a rhombus and regular polygons such as equilateral triangles and squares.  Now, a polygon is equiangular if all of its internal angles are congruent.  Some important facts to consider The only equiangular triangle is the equilateral triangle If P is an equilateral polygon that has more than three sides, it does not have to be equiangular. A rhombus with no right angle is an example of an equilateral but non-equiangular polygon.  Rectangles, including squares, are the only equiangular quadrilaterals Equiangular polygon theorem. Each angle of an equiangular n-gon is  $$\Bigg(\frac{n-2}{n}\Bigg)180^{\circ} = 180^{\circ} -   \frac{360^{\circ}}{n} $$ Viviani's theorem   Vincenzo Viviani (1622 – 1703) was a famous Italian mathematician. With his exceptional intelligence in math...

Prime Factorization

What is the Prime Factorization of a Number?
The prime factorization of a number is the unique set of prime numbers that, when multiplied, make up the number. For example, the prime factorization of the number $20 = 2^2 \cdot 5$, because both $2$ and $5$ are prime numbers. 

Problems that ask you to find the number of factors a given number has are quite common. To solve such problems, first find the prime factorization of your number. Let's take $20$ as an example. As we saw above, $20 = 2^2 \cdot 5$. To find the number of factors that $20$ has, we will add $1$ to each exponent, and then multiply our results. So in this case, we would multiply $(2+1)(1+1) = 3 \cdot 2 = 6$. (Note: the $5$ has an exponent of $1$). 

In general, to find the number of factors of a number, add one to each exponent and calculate the product.

Less common, but still useful is the sum of the factors of a number. We start the same way as before and find the prime factorization of the number. Let's take a look at our example from above and find the sum of all the factors of $20$. To find the sum of these factors, we will find the powers of each prime number, and then calculate the product of these sums. We know $20=2^2 \cdot 5^1$, so putting our formula into action, we get $$(2^0 + 2^1 + 2^2)(5^0+5^1) = (1+2+4)(1+5)=7 \cdot 6 = \boxed{42}$$ 

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